剑指 Offer 53 - I. 在排序数组中查找数字 I

题目链接:https://leetcode-cn.com/problems/zai-pai-xu-shu-zu-zhong-cha-zhao-shu-zi-lcof/

执行用时:0 ms, 在所有 Java 提交中击败了100.00% 的用户
内存消耗:41.4 MB, 在所有 Java 提交中击败了36.74% 的用户

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class Solution {
public int search(int[] nums, int target) {
if (nums.length == 0) {
return 0;
}
int left = 0, right = nums.length - 1;
int start = 0, count = 0;
while (left <= right) {
int mid = left + (right-left)/2;
if (nums[mid] == target) {
start = mid;
break;
} else if (nums[mid] > target) {
right--;
} else {
left++;
}
}
right = start;
left = start-1;
while (right < nums.length) {
if (nums[right] == target) {
count++;
} else {
break;
}
right++;
}
while (left >= 0) {
if (nums[left] == target) {
count++;
} else {
break;
}
left--;
}
return count;
}
}

剑指 Offer 53 - I. 在排序数组中查找数字 I
https://pisces34.github.io/2021/11/08/leetcode/offer53-1/
发布于
2021年11月8日
许可协议